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15p^2+9p-6=0
a = 15; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·15·(-6)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*15}=\frac{-30}{30} =-1 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*15}=\frac{12}{30} =2/5 $
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